(x-10)^2/5=(9x)^1/5

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Solution for (x-10)^2/5=(9x)^1/5 equation:


x in (-oo:+oo)

((x-10)^2)/5 = ((9*x)^1)/5 // - ((9*x)^1)/5

((x-10)^2)/5-(((9*x)^1)/5) = 0

((x-10)^2)/5+(-9/5)*x = 0

((x-10)^2)/5+(-9*x)/5 = 0

(x-10)^2-9*x = 0

x^2-29*x+100 = 0

x^2-29*x+100 = 0

x^2-29*x+100 = 0

DELTA = (-29)^2-(1*4*100)

DELTA = 441

DELTA > 0

x = (441^(1/2)+29)/(1*2) or x = (29-441^(1/2))/(1*2)

x = 25 or x = 4

(x-4)*(x-25) = 0

((x-4)*(x-25))/5 = 0

((x-4)*(x-25))/5 = 0 // * 5

(x-4)*(x-25) = 0

( x-25 )

x-25 = 0 // + 25

x = 25

( x-4 )

x-4 = 0 // + 4

x = 4

x in { 25, 4 }

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